Factor the polynomial completely
-$147 a^{4}-48 b^{2}$
A) $3\left(7 a^{2}+4 b\right)\left(7 a^{2}-4 b\right)$
B) $3\left(7 a^{2}-4 b\right)^{2}$
C) $\left(21 a^{2}+12 b\right)\left(7 a^{2}-4 b\right)$
D) $3\left(7 a^{2}+4 b\right)^{2}$

Question

Quizplus · Accepted Answer

The polynomial $147 a^{4}-48 b^{2}$ can be factored by first factoring out the greatest common factor, which is 3, giving $3(49a^{4} - 16b^{2})$. Recognizing $49a^{4} = (7a^{2})^{2}$ and $16b^{2} = (4b)^{2}$, the expression inside the parentheses can be further factored as a difference of squares: $3[(7a^{2})^{2} - (4b)^{2}]$, which factors into $3(7a^{2} + 4b)(7a^{2} - 4b)$.

Factor the Polynomial Completely - 147a4−48b2147 a^{4}-48 b^{2}147a4−48b2 A) 3(7a2+4b)(7a2−4b)3\left(7 a^{2}+4 b\right)\left(7 a^{2}-4 b\right)3(7a2+4b)(7a2−4b)

Factor the Polynomial Completely
- $147 a^{4}-48 b^{2}$ A) $3\left(7 a^{2}+4 b\right)\left(7 a^{2}-4 b\right)$