Solve the equation
-$2(-2 \mathrm{r}-3)=3$
A) $\frac{3}{4}$
B) $-\frac{9}{4}$
C) $\frac{9}{4}$
D) $-\frac{3}{2}$

Name: Solve the equation -$2(-2 \mathrm{r}-3)=3$ A) $\frac{3}{4}$ B) $-\frac{9}{4}$ C) $\frac{9}{4}$ D) $-\frac{3}{2}$
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Question

Quizplus · Accepted Answer

First, distribute the 2 across the terms inside the parentheses to get $-4r - 6 = 3$. Then, add 6 to both sides to get $-4r = 9$. Finally, divide both sides by -4 to solve for $r$, which gives $r = -\frac{9}{4}$.

Solve the Equation - 2(−2r−3)=32(-2 \mathrm{r}-3)=32(−2r−3)=3 A) 34\frac{3}{4}43​ B) −94-\frac{9}{4}−49​ C) 94\frac{9}{4}49​ D) −32-\frac{3}{2}−23​

Solve the Equation
- $2(-2 \mathrm{r}-3)=3$ A) $\frac{3}{4}$ B) $-\frac{9}{4}$ C) $\frac{9}{4}$ D) $-\frac{3}{2}$