Add. Simplify, if possible.
-$\frac{4}{m-n^{2}}+\frac{9}{n^{2}-m}$
A) $\frac{5}{m-n^{2}}$
B) $\frac{13}{m-n^{2}}$
C) $\frac{36}{m-n^{2}}$
D) $\frac{-5}{m-n^{2}}$

Question

Quizplus · Accepted Answer

The denominators $m-n^{2}$ and $n^{2}-m$ are opposites, so $n^{2}-m=-(m-n^{2})$. Thus, the second fraction becomes $\frac{9}{-(m-n^{2})} = -\frac{9}{m-n^{2}}$. Adding the fractions gives $\frac{4}{m-n^{2}} - \frac{9}{m-n^{2}} = \frac{4-9}{m-n^{2}} = \frac{-5}{m-n^{2}}$.

Add Simplify, If Possible 4m−n2+9n2−m\frac{4}{m-n^{2}}+\frac{9}{n^{2}-m}m−n24​+n2−m9​ A) 5m−n2\frac{5}{m-n^{2}}m−n25​ B) 13m−n2\frac{13}{m-n^{2}}m−n213​ C) 36m−n2\frac{36}{m-n^{2}}m−n236​ D) −5m−n2\frac{-5}{m-n^{2}}m−n2−5​

Add Simplify, If Possible $\frac{4}{m-n^{2}}+\frac{9}{n^{2}-m}$ A) $\frac{5}{m-n^{2}}$ B) $\frac{13}{m-n^{2}}$ C) $\frac{36}{m-n^{2}}$ D) $\frac{-5}{m-n^{2}}$