Solve the problem.
-The product of two consecutive integers is 11 more than their sum. Find the integers.
A) -3 and -2
B) 4 and 5
C) 4,5 or $-3,-2$
D) 3,4 or $-3,-2$

Question

Quizplus · Accepted Answer

Let the two consecutive integers be $x$ and $x+1$. The equation based on the given information is $x(x + 1) = x + (x + 1) + 11$. Simplifying gives $x^2 + x = 2x + 12$, leading to $x^2 - x - 12 = 0$. Factoring the quadratic equation gives $(x - 4)(x + 3) = 0$, so $x = 4$ or $x = -3$. Therefore, the pairs are $4, 5$ and $-3, -2$.

Solve the Problem −3,−2-3,-2−3,−2 D) 3,4 Or −3,−2-3,-2−3,−2

Solve the Problem $-3,-2$ D) 3,4 Or $-3,-2$