Multiply.
-$(x-8)(2 x-12)$
A) $2 x^{2}-28 x+96$
B) $2 x^{2}-28 x-28$
C) $2 x^{2}+96 x-28$
D) $2 x^{2}-30 x+96$

Name: Multiply. -$(x-8)(2 x-12)$ A) $2 x^{2}-28 x+96$ B) $2 x^{2}-28 x-28$ C) $2 x^{2}+96 x-28$ D) $2 x^{2}-30 x+96$
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Question

Quizplus · Accepted Answer

Using the distributive property (FOIL method) to multiply the two binomials: First, $x * 2x = 2x^2$. Outer, $x * -12 = -12x$. Inner, $-8 * 2x = -16x$. Last, $-8 * -12 = 96$. Adding these together: $2x^2 - 12x - 16x + 96 = 2x^2 - 28x + 96$.

Multiply - (x−8)(2x−12)(x-8)(2 x-12)(x−8)(2x−12) A) 2x2−28x+962 x^{2}-28 x+962x2−28x+96 B) 2x2−28x−282 x^{2}-28 x-282x2−28x−28 C) 2x2+96x−282 x^{2}+96 x-282x2+96x−28

Multiply
- $(x-8)(2 x-12)$ A) $2 x^{2}-28 x+96$ B) $2 x^{2}-28 x-28$ C) $2 x^{2}+96 x-28$