Multiply.
-$(-2 y+7)\left(8 y^{2}-y+1\right)$
A) $10 y^{2}-9 y+7$
B) $-16 y^{3}-9 y+7$
C) $-16 y^{3}+58 y^{2}-9 y+7$
D) $-16 y^{3}+54 y^{2}-9 y+7$

Question

Quizplus · Accepted Answer

To multiply the given polynomials, distribute each term of the first polynomial across the second polynomial: $(-2y) * (8y^2) = -16y^3$, $(-2y) * (-y) = 2y^2$, $(-2y) * (1) = -2y$, $7 * (8y^2) = 56y^2$, $7 * (-y) = -7y$, and $7 * (1) = 7$. Combining like terms gives $-16y^3 + (56y^2 + 2y^2) + (-2y - 7y) + 7 = -16y^3 + 58y^2 - 9y + 7$.

Multiply - (−2y+7)(8y2−y+1)(-2 y+7)\left(8 y^{2}-y+1\right)(−2y+7)(8y2−y+1) A) 10y2−9y+710 y^{2}-9 y+710y2−9y+7 B) −16y3−9y+7-16 y^{3}-9 y+7−16y3−9y+7

Multiply
- $(-2 y+7)\left(8 y^{2}-y+1\right)$ A) $10 y^{2}-9 y+7$ B) $-16 y^{3}-9 y+7$