Graph $f(x)=2 \cos (x)+1$ on the interval $-180^{\circ} \leq x \leq 400^{\circ}$. Find the intervals on which
A) $f(x)$ is decreasing.
B) $f(x)$ is concave up.

Name: Graph $f(x)=2 \cos (x)+1$ on the interval $-180^{\circ} \leq x \leq 400^{\circ}$. Find the intervals on which A) $f(x)$ is decreasing. B) $f(x)$ is concave up.
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The Answer of Graph $f(x)=2 \cos (x)+1$ on the interval $-180^{\circ} \leq x \leq 400^{\circ}$. Find the intervals on which
A) $f(x)$ is decreasing.
B) $f(x)$ is concave up.

Graph f(x)=2cos⁡(x)+1f(x)=2 \cos (x)+1f(x)=2cos(x)+1 On the Interval −180∘≤x≤400∘-180^{\circ} \leq x \leq 400^{\circ}−180∘≤x≤400∘

Graph $f(x)=2 \cos (x)+1$ On the Interval $-180^{\circ} \leq x \leq 400^{\circ}$