$\frac{(2 \mathrm{x}-5)(\mathrm{x}+2)}{(\mathrm{x}+8)(\mathrm{x}-3)} \div \frac{(\mathrm{x}+2)(3 \mathrm{x}+5)}{(\mathrm{x}+8)(\mathrm{x}-3)}$

A) $-\frac{2 x-5}{3 x+5}$

B) $\frac{x-8}{x+2}$

C) $\frac{2}{3}$

D) $\frac{2 x-5}{3 x+5}$

Question

$\frac{(2 \mathrm{x}-5)(\mathrm{x}+2)}{(\mathrm{x}+8)(\mathrm{x}-3)} \div \frac{(\mathrm{x}+2)(3 \mathrm{x}+5)}{(\mathrm{x}+8)(\mathrm{x}-3)}$

A) $-\frac{2 x-5}{3 x+5}$

B) $\frac{x-8}{x+2}$

C) $\frac{2}{3}$

D) $\frac{2 x-5}{3 x+5}$

Quizplus · Accepted Answer

Dividing two fractions is equivalent to multiplying the first fraction by the reciprocal of the second. In this case, the (x+2) and (x+8)(x-3) terms cancel out in the division, leaving $\frac{2x-5}{3x+5}$.