Find the missing numerator and denominator.
-$\frac{x+4}{x-7} \cdot \frac{?}{?}=\frac{(x+4)(x-1)}{(x-7)(x+3)}$

A) $\frac{x-1}{x+3}$

B) $\frac{x(x-1)}{x(x+3)}$

C) $\frac{x+1}{x-3}$

D) $\frac{x(4 x-1)}{x(7 x+3)}$

Question

Find the missing numerator and denominator.
-$\frac{x+4}{x-7} \cdot \frac{?}{?}=\frac{(x+4)(x-1)}{(x-7)(x+3)}$

A) $\frac{x-1}{x+3}$

B) $\frac{x(x-1)}{x(x+3)}$

C) $\frac{x+1}{x-3}$

D) $\frac{x(4 x-1)}{x(7 x+3)}$

Quizplus · Accepted Answer

The missing numerator and denominator are $x-1$ and $x+3$ respectively, which makes the equation balanced when multiplied with $\frac{x+4}{x-7}$, resulting in the given expression on the right side.

Find the Missing Numerator and Denominator x+4x−7⋅??=(x+4)(x−1)(x−7)(x+3)\frac{x+4}{x-7} \cdot \frac{?}{?}=\frac{(x+4)(x-1)}{(x-7)(x+3)}x−7x+4​⋅??​=(x−7)(x+3)(x+4)(x−1)​ A) x−1x+3\frac{x-1}{x+3}x+3x−1​ B) x(x−1)x(x+3)\frac{x(x-1)}{x(x+3)}x(x+3)x(x−1)​

Find the Missing Numerator and Denominator $\frac{x+4}{x-7} \cdot \frac{?}{?}=\frac{(x+4)(x-1)}{(x-7)(x+3)}$ A) $\frac{x-1}{x+3}$ B) $\frac{x(x-1)}{x(x+3)}$