$\frac{(\mathrm{x}-2)(\mathrm{x}+3)}{(\mathrm{x}+7)(\mathrm{x}-2)} \cdot \frac{(\mathrm{x}-10)(\mathrm{x}+7)}{(\mathrm{x}+3)(\mathrm{x}+6)}$

A) $\frac{x-10}{x+6}$

B) $-\frac{x-10}{x+6}$

C) $\frac{x+3}{x-2}$

D) $\frac{x+10}{x-6}$

Question

$\frac{(\mathrm{x}-2)(\mathrm{x}+3)}{(\mathrm{x}+7)(\mathrm{x}-2)} \cdot \frac{(\mathrm{x}-10)(\mathrm{x}+7)}{(\mathrm{x}+3)(\mathrm{x}+6)}$

A) $\frac{x-10}{x+6}$

B) $-\frac{x-10}{x+6}$

C) $\frac{x+3}{x-2}$

D) $\frac{x+10}{x-6}$

Quizplus · Accepted Answer

The expression simplifies by canceling out common factors in the numerator and denominator: $(x-2)$, $(x+3)$, and $(x+7)$ leaving $\frac{x-10}{x+6}$.