Find the sum
-$\sum_{i=1}^{4} \frac{i+1}{i+2}$

A) $\frac{6}{7}$

B) $\frac{61}{20}$

C) $\frac{71}{20}$

D) $\frac{21}{10}$

Question

Find the sum
-$\sum_{i=1}^{4} \frac{i+1}{i+2}$

A) $\frac{6}{7}$

B) $\frac{61}{20}$

C) $\frac{71}{20}$

D) $\frac{21}{10}$

Quizplus · Accepted Answer

To find the sum, calculate each term individually and then add them together:1. For $i=1$, $\frac{i+1}{i+2} = \frac{2}{3}$2. For $i=2$, $\frac{i+1}{i+2} = \frac{3}{4}$3. For $i=3$, $\frac{i+1}{i+2} = \frac{4}{5}$4. For $i=4$, $\frac{i+1}{i+2} = \frac{5}{6}$Adding these fractions together: $\frac{2}{3} + \frac{3}{4} + \frac{4}{5} + \frac{5}{6} = \frac{8}{12} + \frac{9}{12} + \frac{48}{60} + \frac{50}{60} = \frac{17}{12} + \frac{98}{60} = \frac{61}{20}$.

Find the Sum - ∑i=14i+1i+2\sum_{i=1}^{4} \frac{i+1}{i+2}∑i=14​i+2i+1​ A) 67\frac{6}{7}76​ B) 6120\frac{61}{20}2061​ C) 7120\frac{71}{20}2071​ D) 2110\frac{21}{10}1021​

Find the Sum
- $\sum_{i=1}^{4} \frac{i+1}{i+2}$ A) $\frac{6}{7}$ B) $\frac{61}{20}$ C) $\frac{71}{20}$ D) $\frac{21}{10}$