Solve for the specified variable.
-$\frac{1}{a}+\frac{1}{b}=\frac{1}{C}$ for $c$
A) $a+b$
B) $\frac{a b}{a+b}$
C) $a b(a+b)$
D) $\frac{a+b}{a b}$

Question

Quizplus · Accepted Answer

To solve for $c$, first, we need to find a common denominator for the fractions on the left side, which is $ab$. This gives us $\frac{b}{ab} + \frac{a}{ab} = \frac{a+b}{ab}$. Since we are solving for $c$ and the equation is given as $\frac{1}{a}+\frac{1}{b}=\frac{1}{C}$, we can equate $\frac{a+b}{ab}$ to $\frac{1}{c}$. Solving for $c$ then gives $c = \frac{ab}{a+b}$, which matches choice B.

Solve for the Specified Variable 1a+1b=1C\frac{1}{a}+\frac{1}{b}=\frac{1}{C}a1​+b1​=C1​ For ccc A) a+ba+ba+b B) aba+b\frac{a b}{a+b}a+bab​ C) ab(a+b)a b(a+b)ab(a+b)

Solve for the Specified Variable $\frac{1}{a}+\frac{1}{b}=\frac{1}{C}$ For $c$ A) $a+b$ B) $\frac{a b}{a+b}$ C) $a b(a+b)$