Solve the problem.
-The sum of two angles is $191^{\circ}$. One angle is $28^{\circ}$ less than twice the other. Find the angles.
A) $71^{\circ}$ and $120^{\circ}$
B) $73^{\circ}$ and $118^{\circ}$
C) $114^{\circ}$ and $77^{\circ}$
D) $71^{\circ}$ and $114^{\circ}$

Question

Quizplus · Accepted Answer

Let the smaller angle be $x$. Then the larger angle is $2x - 28$. The sum of the angles is $x + (2x - 28) = 191$. Solving for $x$, we get $3x - 28 = 191$, so $3x = 219$, and $x = 73$. The other angle is $2(73) - 28 = 118$. Thus, the angles are $73^{\circ}$ and $118^{\circ}$.

Solve the Problem 191∘191^{\circ}191∘ One Angle Is 28∘28^{\circ}28∘ Less Than Twice the Other

Solve the Problem $191^{\circ}$ One Angle Is $28^{\circ}$ Less Than Twice the Other