Solve the problem.
-The product of two consecutive integers is 71 more than their sum. Find the integers.
A) 9 and 10
B) -8 and -7
C) 8,9 or $-8,-7$
D) 9,10 or $-8,-7$

Question

Quizplus · Accepted Answer

The product of two consecutive integers is 71 more than their sum.Let the two consecutive integers be x and x + 1.Then, x(x + 1) = x + x + 1 + 71⇒ x^2 + x = x + 72⇒ x^2 = 72⇒ x = 8 or x = -8Therefore, the two consecutive integers are 8 and 9 or -8 and -7.

Solve the Problem −8,−7-8,-7−8,−7 D) 9,10 Or −8,−7-8,-7−8,−7

Solve the Problem $-8,-7$ D) 9,10 Or $-8,-7$