Factor completely.
-$x^{2}-x-42$
A) $(x+6)(x-7)$
B) $(x+1)(x-13)$
C) $(x-7)(x+7)$
D) $(x+7)(x-6)$

Name: Factor completely. -$x^{2}-x-42$ A) $(x+6)(x-7)$ B) $(x+1)(x-13)$ C) $(x-7)(x+7)$ D) $(x+7)(x-6)$
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Question

Quizplus · Accepted Answer

The correct factorization of $x^2 - x - 42$ is found by looking for two numbers that multiply to -42 and add to -1. The numbers -7 and 6 fit this criterion, so the factorization is $(x+6)(x-7)$.

Factor Completely x2−x−42x^{2}-x-42x2−x−42 A) (x+6)(x−7)(x+6)(x-7)(x+6)(x−7) B) (x+1)(x−13)(x+1)(x-13)(x+1)(x−13) C) (x−7)(x+7)(x-7)(x+7)(x−7)(x+7) D) (x+7)(x−6)(x+7)(x-6)(x+7)(x−6)

Factor Completely $x^{2}-x-42$ A) $(x+6)(x-7)$ B) $(x+1)(x-13)$ C) $(x-7)(x+7)$ D) $(x+7)(x-6)$