Factor using the ac-method.
-$-30 x^{2}-25 x+30$
A) $-5(3 x+2)(2 x-3)$
B) $-5(3 x-2)(2 x+3)$
C) $(-15 x+10)(2 x+3)$
D) prime

Question

Quizplus · Accepted Answer

The ac-method involves multiplying the coefficient of $x^2$ (a) and the constant term (c), which is $-30 \times 30 = -900$. We need two numbers that multiply to $-900$ and add to $-25$. These numbers are $-45$ and $20$. Rewrite the middle term using these numbers: $-30x^2 - 45x + 20x + 30$. Factor by grouping: $-15x(2x + 3) + 10(2x + 3)$. Factor out the common binomial: $(2x + 3)(-15x + 10)$. Simplify: $-5(3x - 2)(2x + 3)$.

Factor Using the Ac-Method −30x2−25x+30-30 x^{2}-25 x+30−30x2−25x+30 A) −5(3x+2)(2x−3)-5(3 x+2)(2 x-3)−5(3x+2)(2x−3) B) −5(3x−2)(2x+3)-5(3 x-2)(2 x+3)−5(3x−2)(2x+3)

Factor Using the Ac-Method $-30 x^{2}-25 x+30$ A) $-5(3 x+2)(2 x-3)$ B) $-5(3 x-2)(2 x+3)$