Factor by grouping.
-$20 x^{2}-25 x-12 x+15$
A) $(5 x-3)(4 x-5)$
B) $(20 x-3)(x-5)$
C) $(20 \mathrm{x}+3)(\mathrm{x}+5)$
D) $(5 x+3)(4 x+5)$

Question

Quizplus · Accepted Answer

First, group the terms: $(20x^2 - 25x) - (12x - 15)$. Factoring out the common factors gives: $5x(4x - 5) - 3(4x - 5)$. Notice that $(4x - 5)$ is a common factor, so the expression can be factored as $(5x - 3)(4x - 5)$.

Factor by Grouping 20x2−25x−12x+1520 x^{2}-25 x-12 x+1520x2−25x−12x+15 A) (5x−3)(4x−5)(5 x-3)(4 x-5)(5x−3)(4x−5) B) (20x−3)(x−5)(20 x-3)(x-5)(20x−3)(x−5)

Factor by Grouping $20 x^{2}-25 x-12 x+15$ A) $(5 x-3)(4 x-5)$ B) $(20 x-3)(x-5)$