Compute the Laplace transform of f(t) = .
A) $ \frac{1}{s}-\frac{1}{s-6} $
B) $ \frac{1}{s}+\frac{1}{(s+6)^{2}} $
C) $ \frac{1}{s}+\frac{1}{(s-6)^{2}} $
D) $ \frac{1}{s(s-6)^{2}} $
E) $ \frac{1}{s(s+6)^{2}} $
F) $ -\frac{1}{s(s-6)} $

Question

Compute the Laplace transform of f(t) =  .
A) $ \frac{1}{s}-\frac{1}{s-6} $ 
B) $ \frac{1}{s}+\frac{1}{(s+6)^{2}} $ 
C) $ \frac{1}{s}+\frac{1}{(s-6)^{2}} $ 
D) $ \frac{1}{s(s-6)^{2}} $ 
E) $ \frac{1}{s(s+6)^{2}} $ 
F) $ -\frac{1}{s(s-6)} $

Quizplus · Accepted Answer

The Answer of Compute the Laplace transform of f(t) =  .
A) $ \frac{1}{s}-\frac{1}{s-6} $ 
B) $ \frac{1}{s}+\frac{1}{(s+6)^{2}} $ 
C) $ \frac{1}{s}+\frac{1}{(s-6)^{2}} $ 
D) $ \frac{1}{s(s-6)^{2}} $ 
E) $ \frac{1}{s(s+6)^{2}} $ 
F) $ -\frac{1}{s(s-6)} $

Compute the Laplace Transform of F(t) = 1s−1s−6 \frac{1}{s}-\frac{1}{s-6} s1​−s−61​ B) 1s+1(s+6)2 \frac{1}{s}+\frac{1}{(s+6)^{2}} s1​+(s+6)21​

Compute the Laplace Transform of F(t) = $\frac{1}{s}-\frac{1}{s-6}$ B) $\frac{1}{s}+\frac{1}{(s+6)^{2}}$