Given u = 2i - j + 2k and v = i - j + 4k, find each of the following:(a) u × v, (b) v × u, and (c) v × v.
A) (a) -2i - 6j - k, (b) 2i + 6j + k, (c) 0
B) (a) -2i - 6j - k, (b) -2i - 6j - k, (c) -4i +8j -4k
C) (a) 2i + 6j + k, (b) -2i - 6j - k, (c) -4i +8j -4k
D) (a) -2i - 6j + k, (b) 2i + 6j - k, (c) 0
E) (a) -2i + 6j - k, (b) 2i - 6j + k, (c) 0

Question

Quizplus · Accepted Answer

The cross product $u \times v$ results in $-2i - 6j - k$, $v \times u$ is the negative of $u \times v$ due to the anticommutative property of cross products, thus $2i + 6j + k$, and $v \times v$ is $0$ because the cross product of any vector with itself is always zero.

Given U = 2i - J + 2k and V