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Evaluate Where S Is the First-Octant Part of the Sphere

Question 62

Multiple Choice

Evaluate $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$ where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.)

A) $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$ $\pi$ $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$
B) $\pi$ $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$
C) $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$ $\pi$ $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$
D) 2 $\pi$ $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$
E) $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$ $\pi$ $Evaluate where S is the first-octant part of the sphere of radius a centred at the origin. (Hint: Even though S is not a closed surface, it is still easiest to use the Divergence Theorem because the integrand in the surface integral is zero on the coordinate planes.) A) \pi B) \pi C) \pi D) 2 \pi E) \pi$

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