Hooke's Law in physics states that if a spring at rest (equilibrium position ) has a weight attached to it, then the distance the spring stretches is directly proportional to the force (weight).
F = kxwhere
F is the force in Newtons(N), x is the distance stretched in meters (m), and k is the spring constant (N/m).A force of 429 N will stretch the spring 33 cm. How much force to the nearest Newtons is required to stretch the spring 72 cm?
A) 196.63 N
B) 936.00 N
C) 1,019,304.00 N
D) 9.36 N

Question

Quizplus · Accepted Answer

To find the force required to stretch the spring 72 cm, first calculate the spring constant k using the given force and stretch: k = F/x = 429 N / 0.33 m. Then use this k to find the new force for 72 cm (0.72 m): F = k * 0.72 m. The calculated force is approximately 936 N.

Hooke's Law in Physics States That If a Spring at Rest