Data Set 10-7: In that long standing feud between the Hatfields and the McCoys, Old Doc Sawbones has been keeping score. During the last 16 years he noted in his feudian notebook a "degree of injury"
measure each time he patched up, sewed up, or made a coroner's report on anyone in the two families. Summary statistics were:
$$\begin{array} { c c c }
& \text { Hatfields } & \text { McCoys } \
\bar { X } & 41 & 34 \
\hat { S } & 6 & 8 \
N & 16 & 16
\end{array}$$
-The standard error of the difference of the data in Data Set 10-7 is
A) 6.25
B) 1.87
C) 0.625
D) 2.50

Question

Data Set 10-7: In that long standing feud between the Hatfields and the McCoys, Old Doc Sawbones has been keeping score. During the last 16 years he noted in his feudian notebook a "degree of injury"
measure each time he patched up, sewed up, or made a coroner's report on anyone in the two families. Summary statistics were:
 $$\begin{array} { c c c } 
& \text { Hatfields } & \text { McCoys } \
\bar { X } & 41 & 34 \
\hat { S } & 6 & 8 \
N & 16 & 16
\end{array}$$
-The standard error of the difference of the data in Data Set 10-7 is
A) 6.25
B) 1.87
C) 0.625
D) 2.50

Quizplus · Accepted Answer

The standard error of the difference is calculated using the formula: $\sqrt{\frac{S_1^2}{N_1} + \frac{S_2^2}{N_2}}$. Substituting the given values: $\sqrt{\frac{6^2}{16} + \frac{8^2}{16}} = \sqrt{\frac{36}{16} + \frac{64}{16}} = \sqrt{6.25} = 2.50$.

Data Set 10-7: in That Long Standing Feud Between the Hatfields