Data Set 11-7: As you may know, there has been some controversy about who the actual author was of plays we today attribute to Shakespeare. Suppose that three critics gave their judgments as to the likelihood (0 to 100%) that each of the three named below was the actual author. $\begin{array} { l c c c } & \begin{array} { c } \text { William } \\\text { Shakespeare }\end{array} & \begin{array} { c } \text { Christopher } \\\text { Marlow }\end{array} & \begin{array} { c } \text { The Duke } \\\text { of Oxford }\end{array} \\ \text { Critic Smythe } & 75 & 25 & 50 \\\text { Critic Jones } & 40 & 10 & 75 \\\text { Critic Jonson } & 90 & 30 & 20\end{array}$
-Regardless of your answer to the questions above, the df_errorfor the numbers in Data Set 11-7 is

Question

Data Set 11-7: As you may know, there has been some controversy about who the actual author was of plays we today attribute to Shakespeare. Suppose that three critics gave their judgments as to the likelihood (0 to 100%) that each of the three named below was the actual author.

\begin{array} { l c c c } & \begin{array} { c } \text { William } \\\text { Shakespeare }\end{array} & \begin{array} { c } \text { Christopher } \\\text { Marlow }\end{array} & \begin{array} { c } \text { The Duke } \\\text { of Oxford }\end{array} \\ \text { Critic Smythe } & 75 & 25 & 50 \\\text { Critic Jones } & 40 & 10 & 75 \\\text { Critic Jonson } & 90 & 30 & 20\end{array}

-Regardless of your answer to the questions above, the df_errorfor the numbers in Data Set 11-7 is

Quizplus · Accepted Answer

The degrees of freedom for a single-factor ANOVA with three groups and three observations per group is calculated as the number of groups minus one, which is $3 - 1 = 2$. However, the question seems to mistakenly ask for the degrees of freedom for the error term, which cannot be directly determined from the information given without additional context such as total number of observations or total degrees of freedom. The correct calculation for the degrees of freedom for the groups (not error) would indeed be 2, but the provided choices do not align with standard ANOVA calculations. The choice B (6) seems to be an error because it does not correspond to any typical degrees of freedom calculation in the context of ANOVA for the given setup.

Data Set 11-7: as You May Know, There Has Been