Given $f ( x ) = \frac { x ^ { 2 } + x - 2 } { x - 1 }$ , find a linear function $g$ which is identical to $f$

Name: Given $f ( x ) = \frac { x ^ { 2 } + x - 2 } { x - 1 }$ , find a linear function $g$ which is identical to $f$
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The Answer of Given $f ( x ) = \frac { x ^ { 2 } + x - 2 } { x - 1 }$ , find a linear function $g$ which is identical to $f$

Given f(x)=x2+x−2x−1f ( x ) = \frac { x ^ { 2 } + x - 2 } { x - 1 }f(x)=x−1x2+x−2​

Given $f ( x ) = \frac { x ^ { 2 } + x - 2 } { x - 1 }$