Let $f ( x ) = \frac { x ^ { 2 } } { 1 + x ^ { 3 } }$ Find $X$ if $f ^ { - 1 } ( x ) = 2$
A) $1 / 2$
B) 9/4
C) 4/9
D) 2/5

Name: Let $f ( x ) = \frac { x ^ { 2 } } { 1 + x ^ { 3 } }$ Find $X$ if $f ^ { - 1 } ( x ) = 2$ A) $1 / 2$ B) 9/4 C) 4/9 D) 2/5
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Quizplus · Accepted Answer

To find $X$, we need $f(X) = 2$. Solving $\frac{X^2}{1 + X^3} = 2$ gives $X^2 = 2 + 2X^3$. Rearranging, we get $2X^3 - X^2 + 2 = 0$. Testing the given options, $X = 4/9$ satisfies this equation.

Let f(x)=x21+x3f ( x ) = \frac { x ^ { 2 } } { 1 + x ^ { 3 } }f(x)=1+x3x2​

Let $f ( x ) = \frac { x ^ { 2 } } { 1 + x ^ { 3 } }$