A variable horizontal force, F, is applied to a 5.0-kg object placed on a flat horizontal plane. The coefficient of static friction between the object and the surface is 0.30. Assuming that the acceleration of gravity is 10 m/s², the range of force that can be applied to the object without initiating any motion is A) 0

Question

A variable horizontal force, F, is applied to a 5.0-kg object placed on a flat horizontal plane. The coefficient of static friction between the object and the surface is 0.30. Assuming that the acceleration of gravity is 10 m/s², the range of force that can be applied to the object without initiating any motion is A) 0 < F. B) 0 < F < 10 N. C) 0 < F < 15 N. D) 0 < F < 35 N.

Quizplus · Accepted Answer

The maximum static friction force can be calculated using the formula $f_{\text{max}} = \mu_s N$, where $\mu_s$ is the coefficient of static friction and $N$ is the normal force. Here, $N = mg = 5.0 \, \text{kg} \times 10 \, \text{m/s}^2 = 50 \, \text{N}$. Thus, $f_{\text{max}} = 0.30 \times 50 \, \text{N} = 15 \, \text{N}$. Therefore, the force applied can be in the range of 0 to 15 N without initiating motion.

A Variable Horizontal Force, F, Is Applied to a 5