How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes?
A)12
B)14
C)16
D)18

Question

Quizplus · Accepted Answer

To encode decimal numbers 0 to 9999, a total of 10,000 unique values need to be represented. The formula to calculate the number of bits required is log2(N), where N is the number of values. log2(10000) is approximately 13.29. Since we can't have a fraction of a bit, we round up to the nearest whole number, which is 14.

How Many Bits Would Be Required to Encode Decimal Numbers