The volume of the solid in the first octant bounded by $x + y + 2 z = 2$ and $2 x + 2 y + z = 4$ is

A)4
B)3
C)2
D)1
E) $\frac { 1 } { 2 }$

Name: The volume of the solid in the first octant bounded by $x + y + 2 z = 2$ and $2 x + 2 y + z = 4$ is A)4 B)3 C)2 D)1 E) $\frac { 1 } { 2 }$
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Question

The volume of the solid in the first octant bounded by $x + y + 2 z = 2$ and $2 x + 2 y + z = 4$ is

A)4
B)3
C)2
D)1
E) $\frac { 1 } { 2 }$

Quizplus · Accepted Answer

The Answer of The volume of the solid in the first octant bounded by $x + y + 2 z = 2$ and $2 x + 2 y + z = 4$ is

A)4
B)3
C)2
D)1
E) $\frac { 1 } { 2 }$

The Volume of the Solid in the First Octant Bounded x+y+2z=2x + y + 2 z = 2x+y+2z=2

The Volume of the Solid in the First Octant Bounded $x + y + 2 z = 2$