The area of the region inside $r = 2 ( 1 + \cos \theta )$ and outside r = 2 is

A) $8 + \frac { \pi } { 2 }$
B) $8 - \frac { \pi } { 2 }$
C) $8 + \pi$
D) $8 - \pi$
E) $\frac { 8 + \pi } { 2 }$

Question

The area of the region inside $r = 2 ( 1 + \cos \theta )$ and outside r = 2 is

A) $8 + \frac { \pi } { 2 }$
B) $8 - \frac { \pi } { 2 }$
C) $8 + \pi$
D) $8 - \pi$
E) $\frac { 8 + \pi } { 2 }$

Quizplus · Accepted Answer

The Answer of The area of the region inside $r = 2 ( 1 + \cos \theta )$ and outside r = 2 is

A) $8 + \frac { \pi } { 2 }$
B) $8 - \frac { \pi } { 2 }$
C) $8 + \pi$
D) $8 - \pi$
E) $\frac { 8 + \pi } { 2 }$

The Area of the Region Inside r=2(1+cos⁡θ)r = 2 ( 1 + \cos \theta )r=2(1+cosθ)