The solution to the differential equation $\frac { d y } { d x } = \frac { \sin x } { \cos y }$ satisfying the boundary condition $y = \frac { \pi } { 2 }$ when $x = 0$ is

A) $\sin y = - \cos x$
B) $\sin y = - \cos x + 1$
C) $\sin y = - \cos x - 1$
D) $\sin y = - \cos x - 2$
E) $\sin y = - \cos x + 2$

Question

The solution to the differential equation $\frac { d y } { d x } = \frac { \sin x } { \cos y }$ satisfying the boundary condition $y = \frac { \pi } { 2 }$ when $x = 0$ is

A) $\sin y = - \cos x$
B) $\sin y = - \cos x + 1$
C) $\sin y = - \cos x - 1$
D) $\sin y = - \cos x - 2$
E) $\sin y = - \cos x + 2$

Quizplus · Accepted Answer

The Answer of The solution to the differential equation $\frac { d y } { d x } = \frac { \sin x } { \cos y }$ satisfying the boundary condition $y = \frac { \pi } { 2 }$ when $x = 0$ is

A) $\sin y = - \cos x$
B) $\sin y = - \cos x + 1$
C) $\sin y = - \cos x - 1$
D) $\sin y = - \cos x - 2$
E) $\sin y = - \cos x + 2$

The Solution to the Differential Equation dydx=sin⁡xcos⁡y\frac { d y } { d x } = \frac { \sin x } { \cos y }dxdy​=cosysinx​

The Solution to the Differential Equation $\frac { d y } { d x } = \frac { \sin x } { \cos y }$