Solve $2 y ( y - 16 ) + 5 ( y - 16 ) = 0$ .
A) $y = 16 , y = - 5$
B) $y = - 16 , y = \frac { 2 } { 5 }$
C) $y = 16 , y = - \frac { 5 } { 2 }$
D) $y = 16 , y = - \frac { 2 } { 5 }$
E) $y = - 16 , y = - \frac { 5 } { 2 }$

Question

Quizplus · Accepted Answer

First, factor out the common term $y - 16$, giving $ ( y - 16 ) ( 2 y + 5 ) = 0 $. Setting each factor equal to zero gives the solutions $y = 16$ and $y = -\frac{5}{2}$.

Solve 2y(y−16)+5(y−16)=02 y ( y - 16 ) + 5 ( y - 16 ) = 02y(y−16)+5(y−16)=0

Solve $2 y ( y - 16 ) + 5 ( y - 16 ) = 0$