Solve the equation of quadratic form. $\frac { 1 } { x ^ { 2 } } - \frac { 3 } { x } - 18 = 0$
A) $x = \frac { 1 } { 3 } ; x = - \frac { 1 } { 6 }$
B) $x = - \frac { 1 } { 3 } ; x = \frac { 1 } { 6 }$
C) $x = 3 ; x = - 6$
D) $x = 9 ; x = 36$
E) $x = - 3 ; x = 6$

Question

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The Answer of Solve the equation of quadratic form. $\frac { 1 } { x ^ { 2 } } - \frac { 3 } { x } - 18 = 0$
A) $x = \frac { 1 } { 3 } ; x = - \frac { 1 } { 6 }$
B) $x = - \frac { 1 } { 3 } ; x = \frac { 1 } { 6 }$
C) $x = 3 ; x = - 6$
D) $x = 9 ; x = 36$
E) $x = - 3 ; x = 6$

Solve the Equation of Quadratic Form 1x2−3x−18=0\frac { 1 } { x ^ { 2 } } - \frac { 3 } { x } - 18 = 0x21​−x3​−18=0

Solve the Equation of Quadratic Form $\frac { 1 } { x ^ { 2 } } - \frac { 3 } { x } - 18 = 0$