Use back-substitution to solve the system of linear equations below. $\left\{ \begin{aligned}
x - y - z & = 3 \
2 y - z & = - 12 \
z & = - 2
\end{aligned} \right.$
A) $( 6,7,2 )$
B) $( 6 , - 7 , - 2 )$
C) $( - 7,6 , - 2 )$
D) $( 7,6,2 )$
E) $( - 6 , - 7 , - 2 )$

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The Answer of Use back-substitution to solve the system of linear equations below. $\left\{ \begin{aligned}
x - y - z & = 3 \
2 y - z & = - 12 \
z & = - 2
\end{aligned} \right.$
A) $( 6,7,2 )$
B) $( 6 , - 7 , - 2 )$
C) $( - 7,6 , - 2 )$
D) $( 7,6,2 )$
E) $( - 6 , - 7 , - 2 )$

Use Back-Substitution to Solve the System of Linear Equations Below {x−y−z=32y−z=−12z=−2\left\{ \begin{aligned}x - y - z & = 3 \\2 y - z & = - 12 \\z & = - 2\end{aligned} \right.⎩⎨⎧​x−y−z2y−zz​=3=−12=−2​

Use Back-Substitution to Solve the System of Linear Equations Below $\left\{ \begin{aligned}x - y - z & = 3 \\2 y - z & = - 12 \\z & = - 2\end{aligned} \right.$