Solve the system of linear equations below by any convenient method. $\left\{ \begin{array} { c }
2 x - 2 y = 2 \
- 2 x + y = - 2
\end{array} \right.$
A) (-2,-1)
B) (-1,0)
C) (1,0)
D) (3,-1)
E) (2,1)

Question

Solve the system of linear equations below by any convenient method. $\left\{ \begin{array} { c } 
2 x - 2 y = 2 \
- 2 x + y = - 2
\end{array} \right.$
A) (-2,-1)
B) (-1,0)
C) (1,0)
D) (3,-1)
E) (2,1)

Quizplus · Accepted Answer

Multiply the second equation by 2 and add the two equations to eliminate $x$:
\begin{align*}
2x-2y&=2 \
-4x+2y&=-4 \
\end{align*}
Adding yields $-2x=-2$, or $x=1$. Substituting into the second equation gives $y=0$. Therefore, the solution is $(1,0)$, which is choice $\boxed{	extbf{(C)}}$.

Solve the System of Linear Equations Below by Any Convenient {2x−2y=2−2x+y=−2\left\{ \begin{array} { c } 2 x - 2 y = 2 \\- 2 x + y = - 2\end{array} \right.{2x−2y=2−2x+y=−2​

Solve the System of Linear Equations Below by Any Convenient $\left\{ \begin{array} { c } 2 x - 2 y = 2 \\- 2 x + y = - 2\end{array} \right.$