Perform the operation. Write the answer in a + bi form. $( 3 + 2 \sqrt { 2 } i ) + ( - 6 - \sqrt { 2 } i )$
A) $- 3 - 2 \sqrt { 2 } i$
B) $- 2 - \sqrt { 2 } i$
C) $- 3 + \sqrt { 2 } i$
D) $- 9 + 2 \sqrt { 2 } i$

Question

Quizplus · Accepted Answer

To add complex numbers, we simply add their real parts and imaginary parts separately. So, 
\begin{align*}
& ( 3 + 2 \sqrt { 2 } i ) + ( - 6 - \sqrt { 2 } i )\
&= (3-6) + (2\sqrt{2}-\sqrt{2}) i \
&= -3 + \sqrt {2} i
\end{align*}

Therefore, the answer is choice C.

Perform the Operation (3+22i)+(−6−2i)( 3 + 2 \sqrt { 2 } i ) + ( - 6 - \sqrt { 2 } i )(3+22​i)+(−6−2​i)

Perform the Operation $( 3 + 2 \sqrt { 2 } i ) + ( - 6 - \sqrt { 2 } i )$