Factor the trinomial square and use the square root method to solve the equation. $x ^ { 2 } - 9 x + 1 = 1$
A) $0$
B) $\pm9$
C) $0 , - 9$
D) $0,9$
E) $9$

Name: Factor the trinomial square and use the square root method to solve the equation. $x ^ { 2 } - 9 x + 1 = 1$ A) $0$ B) $\pm9$ C) $0 , - 9$ D) $0,9$ E) $9$
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Question

Quizplus · Accepted Answer

First, simplify the equation: $x^2 - 9x + 1 = 1$ becomes $x^2 - 9x = 0$. Factoring out an $x$, we get $x(x - 9) = 0$. Setting each factor equal to zero gives the solutions $x = 0$ and $x = 9$.

Factor the Trinomial Square and Use the Square Root Method x2−9x+1=1x ^ { 2 } - 9 x + 1 = 1x2−9x+1=1

Factor the Trinomial Square and Use the Square Root Method $x ^ { 2 } - 9 x + 1 = 1$