Factor the trinomial. Factor out the GCF first. $$24 x ^ { 6 } - 10 x ^ { 4 } - 21 x ^ { 2 }$$
A) $2 x ^ { 2 } \left( 6 x ^ { 2 } - 7 \right) \left( x ^ { 2 } + 3 \right)$
B) $\left( 6 x ^ { 2 } - 7 \right) \left( 4 x ^ { 2 } + 3 \right)$
C) $x ^ { 2 } \left( 6 x ^ { 2 } - 8 \right) \left( 4 x ^ { 2 } - 3 \right)$
D) $x ^ { 2 } \left( 6 x ^ { 2 } - 5 \right) \left( 4 x ^ { 2 } - 3 \right)$
E) $x ^ { 2 } \left( 6 x ^ { 2 } - 7 \right) \left( 4 x ^ { 2 } + 3 \right)$

Question

Quizplus · Accepted Answer

The GCF of the terms is $x^2$. Factoring out the GCF gives $x^2(24x^4-10x^2-21)$. Factoring the trinomial inside the parentheses gives $x^2(6x^2-7)(4x^2+3)$.

Factor the Trinomial 24x6−10x4−21x224 x ^ { 6 } - 10 x ^ { 4 } - 21 x ^ { 2 }24x6−10x4−21x2

Factor the Trinomial $24 x ^ { 6 } - 10 x ^ { 4 } - 21 x ^ { 2 }$