Solve the inequality. Give the result in interval notation. $2 x + 3 22$ A) $( - 4,0 )$ B) $( 4,12 )$ C) $( - 4,8 )$ D) $( - \infty , 4 ) \cup ( 8 , \infty )$ E) $( - \infty , 4 ) \cup ( 12 , \infty )$

Question

Solve the inequality. Give the result in interval notation. $2 x + 3 < 11$ or $3 x - 2 > 22$
A) $( - 4,0 )$
B) $( 4,12 )$
C) $( - 4,8 )$
D) $( - \infty , 4 ) \cup ( 8 , \infty )$
E) $( - \infty , 4 ) \cup ( 12 , \infty )$

Quizplus · Accepted Answer

To solve the inequality, \begin{align*} 2x+3 &< 11 \quad ext{or} \quad 3x-2 > 22 \ 2x &< 8 \quad ext{or} \quad 3x > 24 \ x &< 4 \quad ext{or} \quad x > 8 \ \end{align*} The solution is the union of the intervals $(-\infty, 4)$ and $(8,\infty)$, which is $( - \infty , 4 ) \cup ( 8 , \infty )$. Therefore, the answer is choice D.

Solve the Inequality 2x+3<112 x + 3 < 112x+3<11 Or 3x−2>223 x - 2 > 223x−2>22

Solve the Inequality $2 x + 3 < 11$ Or $3 x - 2 > 22$