Subtract: $$\begin{array} { r }
\frac { 4 } { 7 } \
- \quad \frac { 1 } { 6 } \
\hline
\end{array}$$
A) $\frac { 17 } { 294 }$
B) $\frac { 17 } { 252 }$
C) $\frac { 17 } { 126 }$
D) $\frac { 17 } { 42 }$
E) $\frac { 17 } { 84 }$

Question

Subtract: $$\begin{array} { r } 
\frac { 4 } { 7 } \
- \quad \frac { 1 } { 6 } \
\hline
\end{array}$$
A) $\frac { 17 } { 294 }$
B) $\frac { 17 } { 252 }$
C) $\frac { 17 } { 126 }$
D) $\frac { 17 } { 42 }$
E) $\frac { 17 } { 84 }$

Quizplus · Accepted Answer

To subtract fractions, we need to have a common denominator. The smallest common multiple of 6 and 7 is 42. So, we write:
$$\begin{array} { r } 
\frac { 4\times6 } { 7\times6 } \
- \quad \frac { 1\times7 } { 6\times7 } \
\hline
\end{array}$$
Simplifying the numerators, we get:
$$\frac { 24 } { 42 } - \frac { 7 } { 42 } = \frac { 24-7 } { 42 } = \frac { 17 } { 42 }$$
Therefore, the answer is D, $\frac { 17 } { 42 }$.

Subtract 47−16\begin{array} { r } \frac { 4 } { 7 } \\- \quad \frac { 1 } { 6 } \\\hline\end{array}74​−61​​​

Subtract $\begin{array} { r } \frac { 4 } { 7 } \\- \quad \frac { 1 } { 6 } \\\hline\end{array}$