Solve by the elimination method: $$\begin{array} { l }
10 x + 39 y = 16 \
15 x + 39 y = 18
\end{array}$$
A) $\left( \frac { 1 } { 3 } , \frac { 4 } { 13 } \right)$
B) $\left( \frac { 2 } { 5 } , \frac { 4 } { 13 } \right)$
C) $\left( \frac { 2 } { 5 } , \frac { 1 } { 3 } \right)$
D) $\left( \frac { 1 } { 3 } , \frac { 1 } { 3 } \right)$
E) No solution

Question

Solve by the elimination method: $$\begin{array} { l } 
10 x + 39 y = 16 \
15 x + 39 y = 18
\end{array}$$
A) $\left( \frac { 1 } { 3 } , \frac { 4 } { 13 } \right)$
B) $\left( \frac { 2 } { 5 } , \frac { 4 } { 13 } \right)$
C) $\left( \frac { 2 } { 5 } , \frac { 1 } { 3 } \right)$
D) $\left( \frac { 1 } { 3 } , \frac { 1 } { 3 } \right)$
E) No solution

Quizplus · Accepted Answer

Subtracting the first equation from the second gives $5x = 2$, or $x = \frac{2}{5}$. Substituting $x = \frac{2}{5}$ into the first equation and solving for $y$ gives $y = \frac{4}{13}$.

Solve by the Elimination Method 10x+39y=1615x+39y=18\begin{array} { l } 10 x + 39 y = 16 \\15 x + 39 y = 18\end{array}10x+39y=1615x+39y=18​

Solve by the Elimination Method $\begin{array} { l } 10 x + 39 y = 16 \\15 x + 39 y = 18\end{array}$