Name a, b, and c. $$6 t ^ { 2 } - 54 t = 0$$
A) $a = 6 , b = - 54 , c = 0$
B) $a = 6 , b = 0 , c = - 54$
C) $a = 0 , b = - 54 , c = 6$
D) $a = 0 , b = 6 , c = - 54$
E) $a = - 54 , b = 6 , c = 0$

Question

Quizplus · Accepted Answer

In a quadratic equation of the form $ax^2 + bx + c = 0$, $a$ is the coefficient of $x^2$, $b$ is the coefficient of $x$, and $c$ is the constant term. In the given equation, $6t^2 - 54t = 0$, $a = 6$, $b = -54$, and $c = 0$.

Name A, B, and C 6t2−54t=06 t ^ { 2 } - 54 t = 06t2−54t=0

Name A, B, and C $6 t ^ { 2 } - 54 t = 0$