Find the slope of the line connecting the points. Simplify to eliminate fractions from the numerators and denominators. $$\left( - \frac { b } { 2 } , a \right) , \left( 3 b , \frac { a } { 2 } \right)$$
A) $- \frac { a } { 7 b }$
B) $- \frac { 7 a } { b }$
C) $- \frac { a } { 13 b }$
D) $- \frac { 13 a } { b }$
E) $- \frac { a } { 3 b }$

Question

Quizplus · Accepted Answer

The slope of a line connecting two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $\frac{y_2 - y_1}{x_2 - x_1}$. Applying this formula to the given points $\left( - \frac { b } { 2 } , a \right)$ and $\left( 3 b , \frac { a } { 2 } \right)$, we get the slope as $\frac{\frac { a } { 2 } - a}{3 b - (- \frac { b } { 2 })} = \frac{- \frac { a } { 2 }}{\frac { 7 b } { 2 }} = - \frac { a } { 7 b }$.

Find the Slope of the Line Connecting the Points (−b2,a),(3b,a2)\left( - \frac { b } { 2 } , a \right) , \left( 3 b , \frac { a } { 2 } \right)(−2b​,a),(3b,2a​)

Find the Slope of the Line Connecting the Points $\left( - \frac { b } { 2 } , a \right) , \left( 3 b , \frac { a } { 2 } \right)$