You must use both the class name and the ____ operator when you implement a member function, because they tie the function to the class and allow every instantiated object to use the function name.
A) address
B) dot
C) scope resolution
D) pointer-to-member

Question

Quizplus · Accepted Answer

The scope resolution operator "::" ties the member function to the class and allows every instantiated object to use the function name.

You Must Use Both the Class Name and the ____