Factor the following perfect square trinomial. $4 b ^ { 2 } + 4 b + 1$
A) $( b + 2 ) ^ { 2 }$
B) $( b - 2 ) ^ { 2 }$
C) $( 2 b + 4 ) ^ { 2 }$
D) $( 2 b - 1 ) ^ { 2 }$
E) $( 2 b + 1 ) ^ { 2 }$

Question

Quizplus · Accepted Answer

The given trinomial is a perfect square because it can be written in the form $(a + b)^2 = a^2 + 2ab + b^2$, where $a = 2b$ and $b = 1$, making the factored form $(2b + 1)^2$.

Factor the Following Perfect Square Trinomial 4b2+4b+14 b ^ { 2 } + 4 b + 14b2+4b+1

Factor the Following Perfect Square Trinomial $4 b ^ { 2 } + 4 b + 1$