Find three negative consecutive integers such that the product of the two smaller integers is 142 more than ten times the largest integer.
A) -9, -8, -7
B) -7, -6, -5
C) -12, -11, -10
D) -10, -9, -8
E) -11, -10, -9

Question

Quizplus · Accepted Answer

Let the three consecutive integers be x, x-1, and x-2.Then, (x-1)(x-2) = 142 + 10xx^2 - 3x + 2 = 142 + 10xx^2 - 13x - 140 = 0(x-14)(x+10) = 0x = 14 or x = -10If x = 14, then the three integers are 14, 13, and 12.If x = -10, then the three integers are -10, -11, and -12.Therefore, the correct answer is A.

Find Three Negative Consecutive Integers Such That the Product of the Two