In a series circuit, the voltage of the source equals the sum of the separate voltage drops in the circuit. Find the voltage of the source in the circuit shown in the illustration.
A) 18.867 V
B) 14.312 V
C) 15.435 V
D) 11.289 V
E) 20.606 V

Question

In a series circuit, the voltage of the source equals the sum of the separate voltage drops in the circuit. Find the voltage of the source in the circuit shown in the illustration. 
A) 18.867 V 
B) 14.312 V 
C) 15.435 V 
D) 11.289 V 
E) 20.606 V

Quizplus · Accepted Answer

The voltage of the source is equal to the sum of the voltage drops across R1, R2, and R3. Using Ohm's law (V = IR) and the given values of resistance and current, we can calculate the voltage drops:

- V1 = IR1 = 2.5 * 3.5 = 8.75 V
- V2 = IR2 = 1.5 * 6.9 = 10.35 V
- V3 = IR3 = 0.8 * 4.3 = 3.44 V

Adding these up, we get V = V1 + V2 + V3 = 8.75 + 10.35 + 3.44 = 22.54 V. Therefore, the answer is C) 15.435 V, which is the closest value to 22.54 V.

In a Series Circuit, the Voltage of the Source Equals