To the nearest tenth of square inch, find the area of the regular pentagon whose apothem measures 4.2 inches and whose sides measure 6.2 inches.
A) $64.2 \mathrm { in } ^ { 2 }$
B) $65.1 \mathrm { in } ^ { 2 }$
C) $97.6 \mathrm { in } ^ { 2 }$
D) $130.2 \mathrm { in } ^ { 2 }$

Question

To the nearest tenth of square inch, find the area of the regular pentagon whose apothem  measures 4.2 inches and whose sides measure 6.2 inches.
A) $64.2 \mathrm { in } ^ { 2 }$ 
B) $65.1 \mathrm { in } ^ { 2 }$ 
C) $97.6 \mathrm { in } ^ { 2 }$ 
D) $130.2 \mathrm { in } ^ { 2 }$

Quizplus · Accepted Answer

The formula for finding the area of a regular pentagon is:
A = (1/2)Pa
where A is the area, P is the perimeter (5 × side length), and a is the apothem.

Plugging in the values given, we get:
A = (1/2)5(6.2)(4.2)
A = 65.1 in^2

Therefore, the area to the nearest tenth of a square inch is 65.1 in^2, which corresponds to answer choice B.

To the Nearest Tenth of Square Inch, Find the Area 64.2in264.2 \mathrm { in } ^ { 2 }64.2in2

To the Nearest Tenth of Square Inch, Find the Area $64.2 \mathrm { in } ^ { 2 }$