Evaluate the expression. $\frac { 6 \cdot 7 - 10 ( 7 \cdot 3 - 20 ) } { 4 ( 3 + 2 ) - 3 ^ { 2 } + 5 }$
A) $- 3$
B) $5$
C) $7$
D) $2$
E) $3$

Question

Quizplus · Accepted Answer

First, we simplify the expression in the parenthesis:
$7\cdot 3-20=-1$
Next, we simplify the denominator:
$4(3+2)-3^2+5=-1$
Now we substitute the results:
$\frac {6\cdot 7-10(-1)} {-1}=-42+10=-32$
Therefore, the answer is $\boxed{	extbf{(D)}\ 2}.$

Evaluate the Expression 6⋅7−10(7⋅3−20)4(3+2)−32+5\frac { 6 \cdot 7 - 10 ( 7 \cdot 3 - 20 ) } { 4 ( 3 + 2 ) - 3 ^ { 2 } + 5 }4(3+2)−32+56⋅7−10(7⋅3−20)​

Evaluate the Expression $\frac { 6 \cdot 7 - 10 ( 7 \cdot 3 - 20 ) } { 4 ( 3 + 2 ) - 3 ^ { 2 } + 5 }$