Solve $( x - 7 ) ^ { 2 } = 96$ by the square root property.
A) $\{ - 11 \sqrt { 6 } , \sqrt { 6 } \}$
B) $\{ - \sqrt { 6 } , 11 \sqrt { 6 } \}$
C) $\{ - 7 \pm 4 \sqrt { 6 } \}$
D) $\{ 7 \pm 4 \sqrt { 6 } \}$

Question

Quizplus · Accepted Answer

First, take the square root of both sides to get $x - 7 = \pm \sqrt{96}$. Simplify $\sqrt{96}$ to $4\sqrt{6}$. Then, add 7 to both sides to solve for $x$, resulting in $x = 7 \pm 4\sqrt{6}$.

Solve (x−7)2=96( x - 7 ) ^ { 2 } = 96(x−7)2=96

Solve $( x - 7 ) ^ { 2 } = 96$