Solve and write solution set in interval notation: $8 x - 2

Question

Solve and write solution set in interval notation: $8 x - 2 < x - 4$
A) $\left( - \frac { 2 } { 7 } , \infty \right)$
B) $\left( - \infty , - \frac { 2 } { 7 } \right)$
C) $\left( \frac { 2 } { 7 } , \infty \right)$
D) $\left( - \infty , \frac { 2 } { 7 } \right)$

Quizplus · Accepted Answer

To solve the inequality $8x - 2 < x - 4$, first subtract $x$ from both sides to get $7x - 2 < -4$. Then add 2 to both sides to get $7x < -2$. Finally, divide both sides by 7 to get $x < -\frac{2}{7}$. This means the solution set is all values of $x$ less than $-\frac{2}{7}$, which is represented by the interval notation $\left( -\infty , -\frac{2}{7} \right)$.

Solve and Write Solution Set in Interval Notation 8x−2<x−48 x - 2 < x - 48x−2<x−4

Solve and Write Solution Set in Interval Notation $8 x - 2 < x - 4$